Question:

The \(K_{\alpha}\) and \(K_{\beta}\) X-rays are emitted when there is a transition of electron between the levels

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K-series X-rays always end in \(n=1\): \(K_{\alpha}: 2\to1\), \(K_{\beta}: 3\to1\).
Updated On: Jan 3, 2026
  • \(n = 2 \to n = 1\) and \(n = 3 \to n = 1\) respectively
  • \(n = 2 \to n = 1\) and \(n = 3 \to n = 2\) respectively
  • \(n = 3 \to n = 2\) and \(n = 4 \to n = 3\) respectively
  • \(n = 3 \to n = 2\) and \(n = 4 \to n = 3\) respectively
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The Correct Option is A

Solution and Explanation

Step 1: Understand K-series X-rays.
K-series X-rays are produced when an electron falls into the K-shell (\(n=1\)) from a higher level.
Step 2: Identify \(K_{\alpha}\).
\(K_{\alpha}\) line corresponds to transition from L-shell to K-shell:
\[ n = 2 \to n = 1 \]
Step 3: Identify \(K_{\beta}\).
\(K_{\beta}\) line corresponds to transition from M-shell to K-shell:
\[ n = 3 \to n = 1 \]
Step 4: Match with correct option.
So correct answer is option (A).
Final Answer:
\[ \boxed{\text{(A) } n = 2 \to n = 1 \text{ and } n = 3 \to n = 1} \]
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