The internal angles P, Q, R of a triangle are observed in degree minute second (° ' "). The angles along with their probable errors are given below.
P = 40° 30' 01'' ± 02'', Q = 60° 00' 02'' ± 03'', R = 79° 30' 05'' ± 04''
The corrected values of the angles P, Q and R are
P = 40° 30' 01'' ± 02'', Q = 60° 00' 02'' ± 03'', R = 79° 30' 05'' ± 04''
The corrected values of the angles P, Q and R are
Show Hint
- P = 40° 30' 01'', Q = 60° 00' 02'', R = 79° 30' 05''
- P = 40° 29' 59.6'', Q = 59° 59' 59.5'', R = 79° 30' 0.9''
- P = 40° 29' 59.9'', Q = 59° 59' 59.5'', R = 79° 30' 0.6''
- P = 40° 29' 59'', Q = 59° 59' 59'', R = 79° 30' 02''
The Correct Option is C
Solution and Explanation
The angles are observed with an error margin indicated by ± for each value. For instance, P = 40° 30' 01'' ± 02'' means that the observed value of P could vary by ±2 seconds. So, to get the corrected angle, we need to subtract the error from the observed value. - Angle P: The error for P is ±02'', so we subtract 0.2 from 40° 30' 01'' to get 40° 29' 59.9''.
- Angle Q: The error for Q is ±03'', so we subtract 0.3 from 60° 00' 02'' to get 59° 59' 59.7''. This rounds to 59° 59' 59.5''.
- Angle R: The error for R is ±04'', so we subtract 0.4 from 79° 30' 05'' to get 79° 30' 0.6''.
Step 2: Comparison with options.
By comparing the corrected values with the options, we find that option (C) matches the corrected values exactly. Thus, the correct answer is (C) P = 40° 29' 59.9'', Q = 59° 59' 59.5'', R = 79° 30' 0.6''.
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