To understand where the intensity of the gravitational field of Earth is maximum, we must consider Earth's shape and gravitational principles. Earth is not a perfect sphere but an oblate spheroid; it is slightly flattened at the poles and bulging at the equator. This shape affects how gravitational forces are distributed.
Gravitational field intensity (\(g\)) is determined by the formula:
g = \(\frac{G \cdot M}{r^2}\)
where:
Since the radius (\(r\)) is smaller at the poles compared to the equator due to the Earth's oblate shape, the gravitational field intensity is stronger where \(r\) is smaller. Thus, gravity is strongest at the poles.
The maximum intensity of Earth's gravitational field is observed at the poles, making the correct choice: Poles
Net gravitational force at the center of a square is found to be \( F_1 \) when four particles having masses \( M, 2M, 3M \) and \( 4M \) are placed at the four corners of the square as shown in figure, and it is \( F_2 \) when the positions of \( 3M \) and \( 4M \) are interchanged. The ratio \( \dfrac{F_1}{F_2} = \dfrac{\alpha}{\sqrt{5}} \). The value of \( \alpha \) is 

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].