Let the income of A be \( 9x \) and the income of B be \( 4x \).
Let the expenditure of A be \( 7y \) and the expenditure of B be \( 3y \).
We know that A saves 30% of his income, so the savings of A is:
\[
\text{Savings of A} = 30% \times 9x = 0.30 \times 9x = 2.7x.
\]
The savings of A is also given by:
\[
\text{Savings of A} = \text{Income of A} - \text{Expenditure of A} = 9x - 7y.
\]
Thus,
\[
2.7x = 9x - 7y \quad \Rightarrow \quad 7y = 6.3x \quad \Rightarrow \quad y = 0.9x.
\]
Now, the savings of B is:
\[
\text{Savings of B} = 4x - 3y = 4x - 3(0.9x) = 4x - 2.7x = 1.3x.
\]
Thus, the ratio of the savings of A and B is:
\[
\frac{\text{Savings of A}}{\text{Savings of B}} = \frac{2.7x}{1.3x} = \frac{2.7}{1.3} = \frac{27}{13} = 63 : 32.
\]
Thus, the ratio of their savings is 63 : 32, which corresponds to option (1).