Question:

The hydrogen electrode is dipped in a solution of pH = 3 at 25$^\circ$C. The potential of the cell would be (the value of 2.303 RT/F is 0.059 V)

Updated On: Jun 23, 2023
  • 0.177 V
  • 0.087 V
  • -0.177 V .
  • 0.059V
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The Correct Option is C

Solution and Explanation

$pH = 3$ $\therefore [H^+] = 10^{-3}$ $\therefore [H^+] + e^- {->} \frac{1}{2} H_2$ $E = E^0 - \frac{0.059}{n} \,log \frac{1}{[H^+]} $ $= 0 - \frac{0.059}{1} \,log \,10^3$ $E = - 0.177\,V$
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Notes on Electrolysis

Concepts Used:

Electrolysis

Electrolysis:

Electrolysis is the process by which an element is decomposed and undergoes some chemical change under the influence of any electric current. The first-ever electrolysis was executed out by Sir Humphrey Davey in the year 1808. Electrolysis can occur in both Galvanic cells and Electrolytic cells. 

Applications of Electrolysis:

  1. Electrolytic cells are used for the production of Hydrogen and Oxygen gas from water.
  2. They are used for the large-scale production of pure metals like sodium, copper, magnesium, etc.
  3. They are used to extract Aluminium from Bauxite.
  4. Electrolytic cells are used for electroplating, a process by which a thin protective layer of one metal is formed over another metal, mostly for protection.
  5. Electrolysis is used for the electrorefining of non-ferrous metals.

Read More: Products of Electrolysis