Question:

The hybridisation states of $ [Ni(CO)_4] $ , $ [Ni(CN)_4]^{2-} $ and $ [NiCl_4]^{2-} $ species are respectively

Updated On: Apr 8, 2024
  • $ sp^3 $ , $ sp^3 $ , $ dsp^2 $
  • $ dsp^2 $ , $ sp^3 $ , $ sp^3 $
  • $ sp^3 $ , $ dsp^2 $ , $ dsp^2 $
  • $ sp^3 $ , $ dsp^2 $ , $ sp^3 $
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The Correct Option is D

Solution and Explanation

In the formation of $[Ni(CO)_4]$, oxidation state of $Ni$ is $O$ and its electronic
configuration is $[Ar] \,3d^8\,4s^2$.
Hence, we have



In $[Ni(CN)_4]^{2-}$, $Ni$ is in $+2$ oxidation state and $CN^-$ is a strong ligand and as it approaches the metal ion, the electrons must pair up.



In $[NiCl_4]^{2-}, Cl^-$ provides a weak field ligand. It is therefore, unable to pair up the unpaired electrons of the $3d$ orbitals.


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Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.