Question:
The horizontal component of the earth?s magnetic field is $3.6 \times 10^{-5}$ tesla where the dip angle is $60^{\circ}$. The magnitude of the earth?s magnetic field is
The horizontal component of the earth?s magnetic field is $3.6 \times 10^{-5}$ tesla where the dip angle is $60^{\circ}$. The magnitude of the earth?s magnetic field is
Updated On: Apr 15, 2024
- $2.8\times10^{-4}\,tesla$
- $2.1\times10^{-4}\,tesla$
- $7.2\times10^{-5}\,tesla$
- $3.6\times10^{-5}\,tesla$
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The Correct Option is C
Solution and Explanation
Horizontal component of earth?s field,
$H = Bcos\,\theta,$ since, $\theta = 60^{\circ}$
$3.6\times10^{-5} = B\times\frac{1}{2} \Rightarrow \,B = 7.2\times10^{-5} \,Tesla$
$H = Bcos\,\theta,$ since, $\theta = 60^{\circ}$
$3.6\times10^{-5} = B\times\frac{1}{2} \Rightarrow \,B = 7.2\times10^{-5} \,Tesla$
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Concepts Used:
Types of Magnets
A magnet is a material or artificial setup that can produce a magnetic field around it.
Magnets are of generally three types which are as follows:
- Temporary magnets: Temporary magnets can be magnetized in the presence of a magnetic field. When the magnetic field is removed, these materials lose their magnetic property. Iron nails and paper-clips are examples of the temporary magnet.
- Permanent magnets: Permanent magnets are those magnets that are commonly used. They are known as permanent magnets because they do not lose their magnetic property once they are magnetized. Types of permanent magnets:
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