Question:
The height from earth's surface at which acceleration due to gravity becomes g/ where g is acceleration due to gravity on the surface of earth and R is radius of earth?
The height from earth's surface at which acceleration due to gravity becomes g/ where g is acceleration due to gravity on the surface of earth and R is radius of earth?
Updated On: May 15, 2024
- \(\sqrt2R\)
- \(R\)
- \(\frac{R}{\sqrt{2}}\)
- \(2R\)
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The Correct Option is B
Solution and Explanation
The correct option is (B):\(R\)
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