\(e^x+e^{-y}=C\)
\(e^x+e^y=C\)
\(e^{-x}+e^y=C\)
\(e^{-x}+e^{-y}=C\)
If \(\begin{vmatrix} 2x & 3 \\ x & -8 \\ \end{vmatrix} = 0\), then the value of \(x\) is: