We are given that the function \( f(x, y) \) satisfies the Laplace equation on a circular domain. The general form of the Laplace equation is:
\[
\nabla^2 f(x, y) = 0
\]
This is a partial differential equation, and it describes the behavior of the function \( f(x, y) \) within the circular domain. The Laplace equation is a special case of the Poisson equation, and it is commonly used to describe steady-state heat distribution, electrostatic potential, or fluid flow in physics.
The problem provides the following details:
- The domain is a circle with radius \( r = 1 \), centered at \( (x, y) = (0, 0) \).
- The function \( f(x, y) \) on the boundary of this circle (the boundary is at \( r = 1 \)) has a constant value of 3.
Step 1: General Solution to the Laplace Equation
The general solution to the Laplace equation in polar coordinates, due to the circular symmetry of the problem, will be of the form:
\[
f(r, \theta) = A + Br
\]
where:
- \( A \) and \( B \) are constants determined by the boundary conditions,
- \( r \) is the radial distance from the origin,
- \( \theta \) is the angular coordinate.
Since the problem involves a circular domain, the angular part does not influence the function due to the symmetry, so we can focus only on the radial part.
Step 2: Applying the Boundary Condition
The boundary condition tells us that at \( r = 1 \), the value of the function is equal to 3:
\[
f(1, \theta) = 3
\]
Substitute this into the general solution:
\[
A + B(1) = 3
\]
Thus, we get the equation:
\[
A + B = 3
\]
Step 3: Finding the Value at the Center
To find the value of \( f(0, 0) \), we substitute \( r = 0 \) into the general solution:
\[
f(0, 0) = A + B(0) = A
\]
From the boundary condition, we have \( A + B = 3 \), and since the function is constant on the boundary, we can conclude that \( A = 3 \). Therefore:
\[
f(0, 0) = 3
\]
Thus, the numerical value of \( f(0, 0) \) is 3, making (C) the correct answer.