Step 1: Find the derivative of \( f(x) \)
The first derivative of \( f(x) \) is:
\[
f'(x) = 8x + 24x^3 + 48x^5
\]
Step 2: Set the derivative equal to zero to find critical points
\[
8x + 24x^3 + 48x^5 = 0
\]
Factor out \( 8x \):
\[
8x(1 + 3x^2 + 6x^4) = 0
\]
Thus, \( x = 0 \) is a critical point.
The quadratic \( 1 + 3x^2 + 6x^4 = 0 \) has no real solutions.
Step 3: Analyze the function
Since the function is composed of even powers of \( x \), it has symmetry and no local maxima.
The only critical point is \( x = 0 \), and evaluating the second derivative at \( x = 0 \), we find that \( f(x) \) has a local minimum at this point.
Step 4: Conclusion
Thus, the function has only one minima.