Question:

The Fourier transform of a real-valued time signal has

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Real signals always produce Fourier transforms with conjugate symmetry.
Updated On: Feb 9, 2026
  • odd symmetry
  • even symmetry
  • conjugate symmetry
  • no symmetry
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The Correct Option is C

Solution and Explanation

Step 1: Consider a real-valued signal.
Let $x(t)$ be a real-valued time-domain signal with Fourier transform $X(\omega)$.
Step 2: Apply Fourier symmetry property.
For real signals, the Fourier transform satisfies the conjugate symmetry condition:
\[ X(-\omega) = X^*(\omega) \]
Step 3: Interpretation of symmetry.
This property is known as conjugate symmetry and is characteristic of real-valued signals.
Step 4: Eliminate incorrect options.
Odd or even symmetry alone is insufficient to describe $X(\omega)$.
Step 5: Final conclusion.
Therefore, the Fourier transform of a real-valued signal has conjugate symmetry.
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