Question:

The formation of $ O^{+}_2 [P_t F_6 ]^-$ is the basis for the formation of Xenon fluorides. This is because

Updated On: Apr 2, 2024
  • $O_2$ and $Xe$ have comparable sizes
  • $O_2$ and $Xe$ are gases
  • $O_2$ and $Xe$ have comparable ionisation energies
  • $O_2$ and $Xe$ have comparable electronegativities
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The Correct Option is C

Solution and Explanation

The first ionisation energy of xenon is quite close to that of oxygen and the molecular diameter of xenon and oxygen are almost identical.

Based on the above facts it is suggested that since oxygen combines with $PtF_6$, so xenon should also form similar compound with $PtF_6$
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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: