For two long parallel conductors carrying fixed currents $I_1, I_2$,
\[
\frac{F}{L}=\frac{\mu_0}{2\pi}\,\frac{I_1 I_2}{d}\,.
\]
Thus $\frac{F}{L}\propto \frac{1}{d}$. Doubling the separation $d$ halves the force per unit length:
\[
\left(\frac{F}{L}\right)_{\!new}=\frac{1}{2}\left(\frac{F}{L}\right)_{\!old}
=\frac{1}{2}\times 10=5.0\ \mu\text{N/m}.
\]