Question:

The following system of equations: $$ x_1 + x_2 + x_3 = 1, \quad x_1 + 2x_2 + 3x_3 = 2, \quad x_1 + 4x_2 + \alpha x_3 = 4 $$ has a unique solution. Possible value(s) for $\alpha$ is/are: 

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For unique solutions, ensure the determinant of the coefficient matrix is non-zero.
Updated On: Apr 6, 2025
  • 0
  • Either 0 or 1
  • One of 0, 1, or -1
  • Any real number other than 5
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The Correct Option is D

Solution and Explanation

To determine the unique solution, calculate the determinant of the coefficient matrix: det = α − 8. For a unique solution, the determinant must not be zero: α − 8 ≠ 0. Thus, α can be any real number except 8.
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