The following graph represents the T-V curves of an ideal gas ( where T is the temperature and V the volume) at three pressures P1, P2 and P3 compared with those of Charles's law represented as dotted lines.
Then the correct relation is :
Step 1: Recall Charles’s Law
Charles’s law states that at constant pressure, the volume of an ideal gas is directly proportional to its temperature:
$$ V \propto T \quad \text{(at constant P)} $$
Step 2: Analyze the Graph
In the Temperature-Volume (T-V) graph, the slope of each curve represents:
$$ \text{Slope} = \frac{1}{P} $$
Since pressure (P) is constant for a given curve, a steeper slope indicates a lower pressure.
Step 3: Compare the Slopes
\( P_1 \) has the least slope, indicating the highest pressure.
\( P_3 \) has the steepest slope, indicating the lowest pressure.
Step 4: Conclusion
The correct order of pressures is:
$$ P_1 > P_2 > P_3 $$
Charles’s law states that at constant pressure, the volume of an ideal gas is directly proportional to its temperature:
$$ V \propto T \quad \text{(at constant P)} $$
In the Temperature-Volume (T-V) graph, the slope of each curve represents:
$$ \text{Slope} = \frac{1}{P} $$
Since pressure (P) is constant for a given curve, a steeper slope indicates a lower pressure.
The correct order of pressures is:
$$ P_1 > P_2 > P_3 $$
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The potential (V) at any axial point, at 2 m distance(r) from the centre of the dipole of dipole moment vector
\(\vec{P}\) of magnitude, 4 × 10-6 C m, is ± 9 × 103 V.
(Take \(\frac{1}{4\pi\epsilon_0}=9\times10^9\) SI units)
Reason R : \(V=±\frac{2P}{4\pi \epsilon_0r^2}\), where r is the distance of any axial point, situated at 2 m from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options given below :
The output (Y) of the given logic gate is similar to the output of an/a :