The following graph represents the T-V curves of an ideal gas ( where T is the temperature and V the volume) at three pressures P1, P2 and P3 compared with those of Charles's law represented as dotted lines.

Then the correct relation is :
Step 1: Recall Charles’s Law
Charles’s law states that at constant pressure, the volume of an ideal gas is directly proportional to its temperature:
$$ V \propto T \quad \text{(at constant P)} $$
Step 2: Analyze the Graph
In the Temperature-Volume (T-V) graph, the slope of each curve represents:
$$ \text{Slope} = \frac{1}{P} $$
Since pressure (P) is constant for a given curve, a steeper slope indicates a lower pressure.
Step 3: Compare the Slopes
\( P_1 \) has the least slope, indicating the highest pressure.
\( P_3 \) has the steepest slope, indicating the lowest pressure.
Step 4: Conclusion
The correct order of pressures is:
$$ P_1 > P_2 > P_3 $$
Charles’s law states that at constant pressure, the volume of an ideal gas is directly proportional to its temperature:
$$ V \propto T \quad \text{(at constant P)} $$
In the Temperature-Volume (T-V) graph, the slope of each curve represents:
$$ \text{Slope} = \frac{1}{P} $$
Since pressure (P) is constant for a given curve, a steeper slope indicates a lower pressure.
The correct order of pressures is:
$$ P_1 > P_2 > P_3 $$
Predict the major product $ P $ in the following sequence of reactions:
(i) HBr, benzoyl peroxide
(ii) KCN
(iii) Na(Hg), $C_{2}H_{5}OH$