The following graph represents the T-V curves of an ideal gas ( where T is the temperature and V the volume) at three pressures P1, P2 and P3 compared with those of Charles's law represented as dotted lines.
Then the correct relation is :
Step 1: Recall Charles’s Law
Charles’s law states that at constant pressure, the volume of an ideal gas is directly proportional to its temperature:
$$ V \propto T \quad \text{(at constant P)} $$
Step 2: Analyze the Graph
In the Temperature-Volume (T-V) graph, the slope of each curve represents:
$$ \text{Slope} = \frac{1}{P} $$
Since pressure (P) is constant for a given curve, a steeper slope indicates a lower pressure.
Step 3: Compare the Slopes
\( P_1 \) has the least slope, indicating the highest pressure.
\( P_3 \) has the steepest slope, indicating the lowest pressure.
Step 4: Conclusion
The correct order of pressures is:
$$ P_1 > P_2 > P_3 $$
Charles’s law states that at constant pressure, the volume of an ideal gas is directly proportional to its temperature:
$$ V \propto T \quad \text{(at constant P)} $$
In the Temperature-Volume (T-V) graph, the slope of each curve represents:
$$ \text{Slope} = \frac{1}{P} $$
Since pressure (P) is constant for a given curve, a steeper slope indicates a lower pressure.
The correct order of pressures is:
$$ P_1 > P_2 > P_3 $$
The current passing through the battery in the given circuit, is:
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
A full wave rectifier circuit with diodes (\(D_1\)) and (\(D_2\)) is shown in the figure. If input supply voltage \(V_{in} = 220 \sin(100 \pi t)\) volt, then at \(t = 15\) msec: