Question

Statement X : The percentage increase in number of Registrations from 2004 to 2005 is higher for Managerial candidates than for Technical candidates
Statement Y: The overall Registrations have grown by more than 25%

• A. Only [X] is True
• B. Only [Y] is True
• C. Both [X] and [Y] are True
• D. Neither [X] nor [Y] is True
• A. Only [X] is True
• B. Only [Y] is True
• C. Both [X] and [Y] are True
• D. Neither [X] nor [Y] is True
• A. Only [X] is True
• B. Only [Y] is True
• C. Both [X] and [Y] are True
• D. Neither [X] nor [Y] is True
• A. Only [X] is True
• B. Only [Y] is True
• C. Both [X] and [Y] are True
• D. Neither [X] nor [Y] is True

Answer 1

The Correct Option is C

Step 1: Understand the problem
We have two statements (X and Y) based on the registration data of 2004 and 2005 from the InfiniteJobs.com table. We must check each one separately to verify whether it is true or false.

Step 2: Calculate percentage increase for Technical registrations
Technical registrations in 2004 = 61,205
Technical registrations in 2005 = 63,298
Increase = 63,298 – 61,205 = 2,093
Percentage increase = (2,093 ÷ 61,205) × 100 ≈ 3.42%

Step 3: Calculate percentage increase for Managerial registrations
Managerial registrations in 2004 = 19,236
Managerial registrations in 2005 = 45,292
Increase = 45,292 – 19,236 = 26,056
Percentage increase = (26,056 ÷ 19,236) × 100 ≈ 135.5%

Step 4: Verify Statement X
Technical increase ≈ 3.42%
Managerial increase ≈ 135.5%
Clearly, the increase is much higher for Managerial candidates. Thus, Statement X is True.

Step 5: Calculate overall registrations
Overall 2004 = 61,205 + 19,236 = 80,441
Overall 2005 = 63,298 + 45,292 = 108,590
Increase = 108,590 – 80,441 = 28,149
Percentage increase = (28,149 ÷ 80,441) × 100 ≈ 35%

Step 6: Verify Statement Y
Overall registrations grew by ≈ 35%, which is indeed more than 25%. Thus, Statement Y is also True.

Step 7: Conclusion
Since both Statement X and Statement Y are correct, the answer must be that both are True.

Final Answer: The correct option is (C): Both [X] and [Y] are True

Answer 2

Step 1: Understand the problem
We are asked to check two statements related to drop-outs, i.e., candidates who registered but did not post their CVs. Drop-outs = Registrations – CVs posted. Percentage drop-outs = (Drop-outs ÷ Registrations) × 100.

Step 2: Calculate drop-outs for Managerial category
2004: Registrations = 19,236, CVs posted = 15,389. Drop-outs = 19,236 – 15,389 = 3,847. Percentage drop-outs = (3,847 ÷ 19,236) × 100 ≈ 20%.

2005: Registrations = 45,292, CVs posted = 40,763. Drop-outs = 45,292 – 40,763 = 4,529. Percentage drop-outs = (4,529 ÷ 45,292) × 100 ≈ 10%.

Since 20% → 10%, the percentage of drop-outs decreased for Managerial category. So Statement X is True.

Step 3: Calculate drop-outs for Technical category in 2005
2005: Registrations = 63,298, CVs posted = 60,133. Drop-outs = 63,298 – 60,133 = 3,165. Percentage drop-outs = (3,165 ÷ 63,298) × 100 ≈ 5%.

Step 4: Compare Technical vs. Managerial drop-outs in 2005
Technical drop-outs ≈ 5%. Managerial drop-outs ≈ 10%. Thus, drop-outs were higher for Managerial, not for Technical.
So Statement Y is False.

Step 5: Conclusion
Only Statement X is true, and Statement Y is false.

Final Answer: The correct option is (A): Only [X] is True

Answer 3

Step 1: Understand the problem
We must check the success rate of candidates getting short-listed, which is defined as: Success rate = (Number of short-listed ÷ Number of CVs posted) × 100.
We will calculate this for both Technical and Managerial categories in 2004 and 2005 to verify Statement X and Statement Y.

Step 2: Calculate success rate for Technical in 2005
CVs posted = 60,133 Short-listed = 637 Success rate = (637 ÷ 60,133) × 100 ≈ 1.06%

Step 3: Calculate success rate for Managerial in 2005
CVs posted = 40,763 Short-listed = 399 Success rate = (399 ÷ 40,763) × 100 ≈ 0.98%

Comparison (for 2005): Technical ≈ 1.06%, Managerial ≈ 0.98%. Thus, Technical has the higher success rate. Therefore, Statement X is False.

Step 4: Compare Managerial 2004 vs 2005
2004 (Managerial): CVs posted = 15,389, Short-listed = 138 Success rate = (138 ÷ 15,389) × 100 ≈ 0.90%

2005 (Managerial): Already calculated ≈ 0.98%

Thus, the success rate improved from 0.90% in 2004 to 0.98% in 2005 for Managerial. Therefore, Statement Y is True.

Step 5: Conclusion
Only Statement Y is true, while Statement X is false.

Final Answer: The correct option is (B): Only [Y] is True

Answer 4

Step 1: Understand the problem
We need to evaluate two statements based on 2004 data: - Statement X compares the proportion of offered jobs to CVs posted for Technical vs Managerial. - Statement Y compares the success rate of converting short-listings into offered jobs for Technical vs Managerial.

Step 2: Data from 2004 (Technical)
CVs posted = 59,981 Jobs offered = 181 Short-listed = 684

Proportion (jobs ÷ CVs) = 181 ÷ 59,981 ≈ 0.30% Success rate (jobs ÷ short-listed) = 181 ÷ 684 ≈ 26.5%

Step 3: Data from 2004 (Managerial)
CVs posted = 15,389 Jobs offered = 48 Short-listed = 138

Proportion (jobs ÷ CVs) = 48 ÷ 15,389 ≈ 0.31% Success rate (jobs ÷ short-listed) = 48 ÷ 138 ≈ 34.8%

Step 4: Verify Statement X
Technical proportion = 0.30%, Managerial proportion = 0.31%. So Managerial had a slightly higher proportion. Therefore, Statement X is False.

Step 5: Verify Statement Y
Technical success rate = 26.5%, Managerial success rate = 34.8%. So Managerial had a higher success rate. Therefore, Statement Y is also False.

Step 6: Conclusion
Both Statement X and Statement Y are not true.

Final Answer: The correct option is (D): Neither [X] nor [Y] is True