The figure shows a network diagram for a construction project. The activities A, B, C, D, E, and F are represented by arrows and their durations are in the figure. The total float available for the activity E in day(s) is equal to ......... (round off to the nearest integer).
Calculation of Total Float for Activity E:
- Given Data:
- Duration of Activity E = 4 days.
- Earliest Start Time (EST) of E = 8 (calculated from the preceding activities).
- Latest Finish Time (LFT) of E = 13 (same as the LST of the succeeding activity).
Step 1: Calculate EFT (Earliest Finish Time)
\[ EFT = EST + \text{Duration} = 8 + 4 = 12 \] Step 2: Calculate LST (Latest Start Time)
\[ LST = LFT - \text{Duration} = 13 - 4 = 9 \] Step 3: Compute Total Float
\[ \text{Total Float} = LST - EST = 9 - 8 = 1 \] Final Answer:
The total float for **Activity E** is 1 day. ✅
For the beam and loading shown in the figure, the second derivative of the deflection curve of the beam at the mid-point of AC is given by \( \frac{\alpha M_0}{8EI} \). The value of \( \alpha \) is ........ (rounded off to the nearest integer).
In levelling between two points A and B on the opposite banks of a river, the readings are taken by setting the instrument both at A and B, as shown in the table. If the RL of A is 150.000 m, the RL of B (in m) is ....... (rounded off to 3 decimal places).