The feasible region of an LPP is shown in the figure. If \(Z = 11x + 7y\), then we need to find the maximum value of Z and where it occurs.
\(x + y = 5\) and \(x + 3y = 9\)
Subtract the first equation from the second:
\((x + 3y) - (x + y) = 9 - 5\)
\(2y = 4\)
\(y = 2\)
Substitute y = 2 into the first equation:
\(x + 2 = 5\)
\(x = 3\)
So, the point of intersection is (3, 2).
Now we evaluate Z at the key vertices (3, 2)
If( x +y=5 so 3 + 2 =5, so if points IS (55 It should be : (55),3) and that point ,must verify that it is an feasible points.
At (3, 2): \(Z = 11(3) + 7(2) = 33 + 14 = 47\)
The maximum value of Z is 47, which occurs at (3, 2)
Therefore, ,the correct option is indeed :(D) (3, 2).