Step 1: Recall economic dispatch principle.
For economic load dispatch without transmission losses, the incremental cost (marginal cost) of both units must be equal:
\[
\frac{dF_{1}}{dP_{G1}} = \frac{dF_{2}}{dP_{G2}} = \lambda
\]
Step 2: Compute incremental costs.
\[
\frac{dF_{1}}{dP_{G1}} = 0.2aP_{G1} + 40
\]
\[
\frac{dF_{2}}{dP_{G2}} = 0.4P_{G2} + 30
\]
At initial $a$ and dispatch values $P_{G1} = 175, P_{G2} = 115$:
\[
\lambda = 0.2a(175) + 40 = 35a + 40
\]
\[
\lambda = 0.4(115) + 30 = 46 + 30 = 76
\]
So,
\[
35a + 40 = 76 \Rightarrow 35a = 36 \Rightarrow a \approx 1.0286
\]
Step 3: Effect of increasing $a$ by 10%.
New $a' = 1.0286 \times 1.1 \approx 1.1314$
Now, the marginal cost of generator 1 increases faster with $P_{G1}$ because the coefficient $0.2a$ has increased. To restore equality of incremental costs:
- $P_{G1}$ must decrease (so that $\frac{dF_{1}}{dP_{G1}}$ reduces).
- Correspondingly, $P_{G2}$ must increase to keep the total load constant at $290 \, MW$.
Step 4: Effect on total cost $F$.
Since the unit 1 cost curve has become "steeper" (more expensive per MW), and more generation shifts to unit 2, the overall total cost $F$ will increase.
Step 5: Final outcome.
\[
P_{G1} \; \text{decreases}, F \; \text{increases}.
\]
% Final Answer
\[
\boxed{\text{Option (A): $P_{G1}$ decreases and $F$ increases.}}
\]
In the Wheatstone bridge shown below, the sensitivity of the bridge in terms of change in balancing voltage \( E \) for unit change in the resistance \( R \), in V/Ω, is __________ (round off to two decimal places).
The relationship between two variables \( x \) and \( y \) is given by \( x + py + q = 0 \) and is shown in the figure. Find the values of \( p \) and \( q \). Note: The figure shown is representative.