The experimental data for the reaction \(2 A + B_2 \longrightarrow 2 AB\) is The rate equation for the above data is
Exp. | [A] | \([B_2]\) | Rate \((M\,s^{-1})\) |
---|---|---|---|
1 | 0.50 | 0.50 | \(1.6 \times 10^{-4}\) |
2. | 0.05 | 1.00 | \(3.2 \times 10^{-4}\) |
3. | 1.00 | 1.00 | \(3.2 \times 10^{-4}\) |
Consider the following rate law equation,
\(\hspace15mm \frac{dx}{dt}=k [A]^m [B_2]^n\)
\(\, \, \, \, \, \, \, 1.6 \times 10^{-4}=k [0.50]^m [0.50]^n \hspace20mm ...(i)\)
\(\, \, \, \, \, \, \, 3.2 \times 10^{-4}=k [0.50]^m [1.0]^n \hspace20mm ...(ii)\)
\(\, \, \, \, \, \, \, 3.2 \times 10^{-4}=k [1.00]^m [1.0]^n \hspace20mm ...(iii)\)
From Eqs. (ii) and (iii)
\(\, \, \, \, \, \, \, \, \frac{3.2 \times 10^{-4}}{3.2 \times 10^{-4}}=\frac{k [1.00]^m [1.0]^n}{k [0.50]^m [1.0]^n}\)
\(\, \, \, \, \, \, \, \, \, \, \, \, 1 =2^m \, \, \, \, or \, \, \, \, 2^0=2^m\)
\(\therefore \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, m=0\)
From Eqs. (i) and (ii)
\(\, \, \, \, \, \, \, \, \frac{3.2 \times 10^{-4}}{1.6 \times 10^{-4}}=\frac{k [0.50]^m [1.0]^n}{k [0.50]^m [0.50]^n}\)
\(\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, 2= 2^n\)
or \(\, \, \, \, \, \, \, \, \, \, \, \, \, 2^1=2^n\)
\(\therefore \, \, \, \, \, \, \, \, \, \, n=1\)
Hence, rate
\(\hspace15mm \big(\frac{dx}{dt}\big)=k [A]^0 [B_2]^1\)
\(\hspace25mm =k [B_2]\)
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A broad meaning of the term "reaction rate" is the pace at which a reaction occurs. For instance, the oxidation of iron has a low response rate because the process is long, but burning wood has a high reaction rate because the process is quick.
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Here, A and B denote reactants and C and D denote products
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