Question:

The escape velocity from the surface of Earth is 11.2 km/s. If the radius of Earth is doubled and mass remains the same, the new escape velocity will be:

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Escape velocity varies inversely with square root of radius.
Updated On: Jan 5, 2026
  • 11.2 km/s
  • 7.92 km/s
  • 15.84 km/s
  • 22.4 km/s
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The Correct Option is B

Solution and Explanation

\[ v_e \propto \frac{1}{\sqrt{R}} \] \[ v'=\frac{11.2}{\sqrt{2}}=7.92\ \text{km/s} \]
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