Question

The equivalent capacitance of the combination of the capacitors is:

• A. 3.20 µF
• B. 7.80 µF
• C. 3.90 µF
• D. 2.16 µF

Hint:

For capacitors in series, the reciprocal of the total capacitance is the sum of the reciprocals of individual capacitances.

Answer 1

The Correct Option is B

Step 1: Capacitance formula for series and parallel combinations.
The equivalent capacitance for capacitors in parallel is: \[ C_{\text{eq}} = C_1 + C_2 + \cdots \] For capacitors in series: \[ \frac{1}{C_{\text{eq}}} = \frac{1}{C_1} + \frac{1}{C_2} + \cdots \] Step 2: Given combination of capacitors.
The capacitors are arranged in a combination of series and parallel. By applying the above formulas and calculating the equivalent capacitance, we obtain the final result as 7.80 µF.
Final Answer: \[ \boxed{7.80 \, \mu F} \]