The equivalent capacitance between A and B in the given figure is:
Show Hint
For capacitors in series and parallel, use the formulas \( \frac{1}{C_{\text{eq}}} = \frac{1}{C_1} + \frac{1}{C_2} \) for series and \( C_{\text{eq}} = C_1 + C_2 \) for parallel combinations.
By combining the capacitors step by step in series and parallel, we find the equivalent capacitance between points A and B to be \( \frac{4}{3} \, \mu F \).
Thus, the correct answer is option (4).