Question

The equivalent capacitance between a and b for the combination of capacitors shown in figure where all capacitances are in microfarad is:

• A. 6.0 \( \mu \)F
• B. 4.0 \( \mu \)F
• C. 2.0 \( \mu \)F
• D. 3.0 \( \mu \)F

Hint:

When calculating equivalent capacitance, remember that capacitors in series have an inverse relationship, while capacitors in parallel add directly.

Answer 1

The Correct Option is A

Step 1: The equivalent capacitance of capacitors in series and parallel must be calculated. For capacitors in series, \( \dfrac{1}{C_{\text{eq}}} = \dfrac{1}{C_1} + \dfrac{1}{C_2} + \dots \), and for capacitors in parallel, \( C_{\text{eq}} = C_1 + C_2 + \dots \).
Step 2: By applying these formulas to the given combination of capacitors, the equivalent capacitance is calculated to be 6.0 \( \mu \)F.

Final Answer: \[ \boxed{6.0 \, \mu \text{F}} \]