Question:
The equation of a circle passing through the point (1, 1) and the point of intersection of the circles x2 + y2 + 13x - 3y = 0 and 2x2 + 2y2 + 4x - 7y -25 = 0 is
The equation of a circle passing through the point (1, 1) and the point of intersection of the circles x2 + y2 + 13x - 3y = 0 and 2x2 + 2y2 + 4x - 7y -25 = 0 is
Updated On: Nov 1, 2024
- 4x2 + 4y2 + 30x - 13y - 25 = 0
- 4x2 + 4y2 + 30x - 13y + 25 = 0
- 4x2 - 4y2 - 30x + 13y - 25 = 0
- 4x2 - 4y2 + 30x - 13y - 25 = 0
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The Correct Option is A
Solution and Explanation
The correct option is (A) : 4x2 + 4y2 + 30x - 13y - 25 = 0.
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