The option in the image that is check-marked is (b): \( \frac{1}{2\zeta \sqrt{1 - 2\zeta^2}} \)
The standard formula for resonant peak \( M_r \) is:
\[ M_r = \frac{1}{2\zeta \sqrt{1 - \zeta^2}} \]
This is valid for \( 0 < \zeta < \frac{1}{\sqrt{2}} \approx 0.707 \).
The resonant frequency \( \omega_r \) is given by:
\[ \omega_r = \omega_n \sqrt{1 - 2\zeta^2} \]
This also only exists for \( 0 < \zeta < \frac{1}{\sqrt{2}} \).
Option (b) is given as:
\[ \frac{1}{2\zeta \sqrt{1 - 2\zeta^2}} \]
This is not the standard formula for resonant peak \( M_r \), but the square root term here matches the one from the resonant frequency formula \( \omega_r \). Hence, it appears the option confuses the formulas.
Given the standard definition of resonant peak magnitude \( M_r \), the correct formula is:
\[ \frac{1}{2\zeta \sqrt{1 - \zeta^2}} \]
Option (b) is incorrect for this definition. There is likely an error in the options or a misinterpretation of what the question asks. If it asks for \( \frac{\omega_r}{\omega_n} \), then the square root term in (b) would be appropriate, but not for \( M_r \).
Final Note: Option (b) is marked, but it does not match the standard formula for resonant peak. The question or options may be flawed.
Consider the unity-negative-feedback system shown in Figure (i) below, where gain \( K \geq 0 \). The root locus of this system is shown in Figure (ii) below.
For what value(s) of \( K \) will the system in Figure (i) have a pole at \( -1 + j1 \)?

Consider a message signal \( m(t) \) which is bandlimited to \( [-W, W] \), where \( W \) is in Hz. Consider the following two modulation schemes for the message signal:
• Double sideband-suppressed carrier (DSB-SC): \[ f_{DSB}(t) = A_c m(t) \cos(2\pi f_c t) \] • Amplitude modulation (AM): \[ f_{AM}(t) = A_c \left( 1 + \mu m(t) \right) \cos(2\pi f_c t) \] Here, \( A_c \) and \( f_c \) are the amplitude and frequency (in Hz) of the carrier, respectively. In the case of AM, \( \mu \) denotes the modulation index. Consider the following statements:
(i) An envelope detector can be used for demodulation in the DSB-SC scheme if \( m(t)>0 \) for all \( t \).
(ii) An envelope detector can be used for demodulation in the AM scheme only if \( m(t)>0 \) for all \( t \).
Which of the following options is/are correct?