Question

The energy diagram of a hydrogen atom is given below. Arrange the wavelengths corresponding to different emissions in increasing order.

• A. \( \lambda_D>\lambda_B>\lambda_A>\lambda_C \)
• B. \( \lambda_D>\lambda_C>\lambda_B>\lambda_A \)
• C. \( \lambda_A>\lambda_C>\lambda_B>\lambda_D \)
• D. \( \lambda_A>\lambda_B>\lambda_C>\lambda_D \)

Hint:

In atomic transitions, the larger the energy difference, the shorter the wavelength of the emitted radiation.

Answer 1

The Correct Option is D

The energy levels of the hydrogen atom are depicted as follows: - The energy difference between level D and A (13.6 eV to 0.85 eV) corresponds to the longest wavelength \( \lambda_A \). - The energy difference between levels C and A (3.4 eV to 0.85 eV) corresponds to \( \lambda_B \). - The energy difference between B and A (1.5 eV to 0.85 eV) corresponds to \( \lambda_C \). - The smallest energy difference corresponds to \( \lambda_D \). Thus, the order of wavelengths from longest to shortest is: \( \lambda_A>\lambda_B>\lambda_C>\lambda_D \).