Question:
The elements with atomic numbers 19, 37 and 55
The elements with atomic numbers 19, 37 and 55
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Alkali metals (Group 1) always have the lowest ionization energies in their periods.
Updated On: Dec 14, 2025
- form cubic chloride salts with the coordination number of cation being 6
- form ionic fluorides with general formula MF
- have lowest density of solids in their respective periods
- have lowest ionization energy in their respective periods
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The Correct Option is B, C, D
Solution and Explanation
Step 1: Identify the elements.
Atomic numbers: 19 → K (Potassium), 37 → Rb (Rubidium), 55 → Cs (Cesium). These are alkali metals of Group 1.
Step 2: Analyze options.
(A) Incorrect — Their chlorides form ionic solids but not necessarily with CN = 6. (B) Incorrect — Fluorides are MF, but this is true for all alkali metals and does not distinguish these atoms. (C) Incorrect — Lithium has lower density than sodium; group trends vary. (D) Correct — Alkali metals always have the lowest ionization energies in each period.
Step 3: Conclusion.
Thus, these elements have the lowest ionization energies in their respective periods.
Atomic numbers: 19 → K (Potassium), 37 → Rb (Rubidium), 55 → Cs (Cesium). These are alkali metals of Group 1.
Step 2: Analyze options.
(A) Incorrect — Their chlorides form ionic solids but not necessarily with CN = 6. (B) Incorrect — Fluorides are MF, but this is true for all alkali metals and does not distinguish these atoms. (C) Incorrect — Lithium has lower density than sodium; group trends vary. (D) Correct — Alkali metals always have the lowest ionization energies in each period.
Step 3: Conclusion.
Thus, these elements have the lowest ionization energies in their respective periods.
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