Step 1: Formula for electrostatic energy of a charged spherical shell.
The electrostatic energy of a uniformly charged spherical shell is given by:
\[
U = \frac{1}{8 \pi \epsilon_0} \int_S \sigma \, r^2 \, d\Omega
\]
where \( \sigma \) is the surface charge density, and \( r \) is the radius of the shell. Since the total charge \( Q \) is 5 C, the surface charge density \( \sigma \) is:
\[
\sigma = \frac{Q}{4\pi r^2} = \frac{5}{4\pi \times 4^2} = \frac{5}{4\pi \times 16} = \frac{5}{64\pi} \, \text{C/m}^2
\]
Step 2: Calculate the electrostatic potential energy.
Using the formula for the energy stored in a spherical shell:
\[
U = \frac{3Q^2}{5R}
\]
where \( R = 4 \, \text{m} \) is the radius of the shell. Substituting the values:
\[
U = \frac{3 \times 5^2}{5 \times 4} = \frac{3 \times 25}{20} = 3.75 \, \text{J}
\]
Step 3: Convert the answer to the desired units.
Finally, in terms of the given units:
\[
U = 3.75 \times 10^9 \, \frac{1}{4 \pi \epsilon_0} \, \text{J}
\]
Thus, the correct answer is 1.781 \( \times 10^9 \).