Question

The electrode reaction that takes place at the anode of CH\(_3\)OH - O\(_2\) fuel cell is:

• A. 2O\(_2\) + 8H\(^+\) + 8e\(^-\) \( \rightarrow \) 4H\(_2\)O
• B. CH\(_3\)OH \( \rightarrow \) CO\(_2\) + 8H\(^+\) + 8e\(^-\)
• C. CH\(_3\)OH \( \rightarrow \) CO\(_2\) + H\(_2\)O
• D. CO\(_2\) \( \rightarrow \) CO

Hint:

At the anode of a fuel cell, the fuel is oxidized, releasing electrons that flow through the external circuit.

Answer 1

The Correct Option is B

Step 1: Identify the anode reaction. At the anode of a fuel cell, the fuel (in this case, methanol) undergoes oxidation. In the case of methanol fuel cells, methanol is oxidized to carbon dioxide, releasing electrons and protons.
Step 2: Conclusion. Thus, the correct reaction at the anode is: \[ \text{CH}_3\text{OH} \rightarrow \text{CO}_2 + 8\text{H}^+ + 8e^- \]