Question

The electric power (in kWh) consumed in operating a 60 W bulb for 3 hours a day in a month of 30 days is

• A. 2.7
• B. 5.4
• C. 8
• D. 36

Answer 1

The Correct Option is B

We are given the following data:
Power of the bulb = 60 W,
Time of operation per day = 3 hours,
Number of days in a month = 30 days.
The energy consumed by the bulb per day is: \[ \text{Energy per day (in Wh)} = \text{Power} \times \text{Time} = 60 \, \text{W} \times 3 \, \text{hours} = 180 \, \text{Wh}. \] Since 1 kWh = 1000 Wh, the energy consumed per day in kWh is: \[ \text{Energy per day (in kWh)} = \frac{180}{1000} = 0.18 \, \text{kWh}. \] The total energy consumed in 30 days is: \[ \text{Total energy in 30 days} = 0.18 \, \text{kWh/day} \times 30 \, \text{days} = 5.4 \, \text{kWh}. \]

The correct option is (B): \(5.4\)