Question:

The electric potential $V$ at any point $(x, y, z)$, all in metres in space is given by $V = 4x^2$ volt. The electric field at the point $(1, 0, 2)$ in volt/meter, is

Updated On: Jul 29, 2022
  • 8 along negative X-axis
  • 8 along positive X-axis
  • 16 along negative X-axis
  • 16 along positive X-axis
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The Correct Option is A

Solution and Explanation

$\vec{ E }=-\left[\hat{ i } \frac{\partial V }{\partial x }+\hat{ j } \frac{\partial V }{\partial y }+\hat{ k } \frac{\partial V }{\partial z }\right] $ $\vec{ E }=-[\hat{ i }(8 x )] $ $\vec{ E }_{(1,0,2)}=-8 \hat{ i }$ So electric field is 8 along negative $x$ -axis.
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Concepts Used:

Electric Field

Electric Field is the electric force experienced by a unit charge. 

The electric force is calculated using the coulomb's law, whose formula is:

\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)

While substituting q2 as 1, electric field becomes:

 \(E=k\dfrac{|q_{1}|}{r^{2}}\)

SI unit of Electric Field is V/m (Volt per meter).