Question:

The electric field strength at a distance r from a charge q is E. What will be electric field strength if the distance of the observation point is increased to 2 r?

Updated On: Jul 7, 2022
  • E/2
  • E/4
  • E/6
  • none of the above
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The Correct Option is B

Solution and Explanation

As new distance = 2 r and electric field due to single charge, $E \propto \frac{1}{r^2}$ , therefore, new intensity $ = E/4$.
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Notes on Electric Field

Concepts Used:

Electric Field

Electric Field is the electric force experienced by a unit charge. 

The electric force is calculated using the coulomb's law, whose formula is:

\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)

While substituting q2 as 1, electric field becomes:

 \(E=k\dfrac{|q_{1}|}{r^{2}}\)

SI unit of Electric Field is V/m (Volt per meter).