Question:
The electric field components in the given figure are $E_x = \alpha x^{1/2}$, $E_y = E_z = 0$ in which $\alpha = 800\, N\, C^{-1}\, m^{-1/2}$. The charge within the cube if net flux through the cube is $1.05\, N\, m^2\,C^{-1}$ (assume $a = 0.1\, m$)
The electric field components in the given figure are $E_x = \alpha x^{1/2}$, $E_y = E_z = 0$ in which $\alpha = 800\, N\, C^{-1}\, m^{-1/2}$. The charge within the cube if net flux through the cube is $1.05\, N\, m^2\,C^{-1}$ (assume $a = 0.1\, m$)
Updated On: Jul 7, 2022
- $9.27 \times 10^{-12}\, C$
- $9.27 \times 10^{12}\, C$
- $6.97 \times 10^{-12}\, C$
- $6.97 \times 10^{12}\, C$
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The Correct Option is A
Solution and Explanation
By Gauss?? law, $\phi=\frac{q}{\varepsilon_{0}}$
or $q=\phi\varepsilon_{0}$
$=1.05\times8.854\times10^{-12}\,C$
$=9.27\times10^{12}\,C$
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Concepts Used:
Electric Field
Electric Field is the electric force experienced by a unit charge.
The electric force is calculated using the coulomb's law, whose formula is:
\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)
While substituting q2 as 1, electric field becomes:
\(E=k\dfrac{|q_{1}|}{r^{2}}\)
SI unit of Electric Field is V/m (Volt per meter).