The electric field is an imaginary field that originated from a positive charge and ends on a negative charge.
The electric field at a point is continuous if there is no negative or positive electric charge in its vicinity that affects its pathway. The presence of any charge in the pathway of the electric field makes it discontinuous. So both options (b) and (c) are correct.

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The Correct Answer is (D)
1. The electric field is strongest at the surface of a particle and decreases as you move away from the particle.
2. There is a uniform electric field between two charged plates, which means both the magnitude and direction of the electric field are the same at all points between the plates.
3. The electric field inside a conductor is zero because the charges in the conductor are free to move and they will redistribute themselves so that the electric field is zero.

1. What is the electric field at a point?
2. How is the electric field at a point determined?
3. What are the units of the electric field?
4. What are some examples of the electric field at a point?
The Correct Answer is (D)
The electric field is a region or space around a charged body within which its influence can be felt by other small charges. The intensity of the electric field due to a source charge at a point is the force experienced by a test charge placed at that point.
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Net dipole moment of a polar linear isotropic dielectric substance is not zero even in the absence of an external electric field. Reason
(R): In absence of an external electric field, the different permanent dipoles of a polar dielectric substance are oriented in random directions.
In the light of the above statements, choose the most appropriate answer from the options given below:
Two large plane parallel conducting plates are kept 10 cm apart as shown in figure. The potential difference between them is $ V $. The potential difference between the points A and B (shown in the figure) is: 
A metallic ring is uniformly charged as shown in the figure. AC and BD are two mutually perpendicular diameters. Electric field due to arc AB to O is ‘E’ magnitude. What would be the magnitude of electric field at ‘O’ due to arc ABC? 
Electric Field is the electric force experienced by a unit charge.
The electric force is calculated using the coulomb's law, whose formula is:
\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)
While substituting q2 as 1, electric field becomes:
\(E=k\dfrac{|q_{1}|}{r^{2}}\)
SI unit of Electric Field is V/m (Volt per meter).