Question:

The earth?s mass is 80 80 times that of moon and their diameters are 1600km 1600 \,km and 800km 800 \,km , respectively. If g g is the value of acceleration due to gravity on earth, what is its value on moon?

Updated On: Jun 6, 2024
  • g g
  • g/2 g/2
  • g/10 g/10
  • g/20 g/20
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The Correct Option is D

Solution and Explanation

Acceleration due to gravity on earth,
g=GMeRe2g=\frac{GM_{e}}{R_{e}^{2}}
=G×80Mm(800)2=\frac{G\times80M_{m}}{\left(800\right)^{2}}
=GMm8×103(i)=\frac{GM_{m}}{8\times10^{3}} \ldots\left(i\right)
Acceleration due to gravity on moon,
gm=GMmRm2g_{m}=\frac{GM_{m}}{R_{m}^{2}}
=G×Mm(400)2=\frac{G\times M_{m}}{\left(400\right)^{2}}
=GMm160×103=\frac{GM_{m}}{160\times10^{3}}
gm=8g160\therefore g_{m}=\frac{8g}{160}
gm=g20\Rightarrow g_{m}=\frac{g}{20} (using (i))
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Concepts Used:

Newtons Law of Gravitation

Gravitational Force

Gravitational force is a central force that depends only on the position of the test mass from the source mass and always acts along the line joining the centers of the two masses.

Newton’s Law of Gravitation:

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • Directly proportional to the product of their masses i.e. F ∝ (M1M2) . . . . (1)
  • Inversely proportional to the square of the distance between their center i.e. (F ∝ 1/r2) . . . . (2)

By combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2 [f(r)is a variable, Non-contact, and conservative force]