Step 1: Use the equation of motion.
The distance travelled in the \(n^{\text{th}}\) second is given by the equation:
\[
S_n = u + \frac{a(2n-1)}{2}
\]
where \( u \) is the initial velocity, \( a \) is the acceleration, and \( n \) is the second.
Step 2: Apply the values.
For the third second, we have \( u = 0 \), \( a = 3 \, \text{m/s}^2 \), and \( n = 3 \). Substituting these values, we get:
\[
S_3 = 0 + \frac{3(2(3)-1)}{2} = 20 \, \text{m}.
\]