
Here AD and CE are the 2 trees and the heights are 28 m and 20 m respectively
As given in the question AC which is the distance between two trees= 17 m
According to the pythagoras theorem = \(AC^2 = AB^2 + BC^2\)
= \(17^2 = 8^2 + BC^2\)
= 289 = 64 + \(BC^2\)
= \(289 - 64 = BC^2\)
= \(225 = BC^2\)
\(BC = \sqrt{225}\)
\(BC = 15\ cm\)
The correct option is (C): 15 m
If \( \theta \in \left[ -\frac{7\pi}{6}, \frac{4\pi}{3} \right] \), then the number of solutions of \[ \sqrt{3} \csc^2 \theta - 2(\sqrt{3} - 1)\csc \theta - 4 = 0 \] is equal to ______.