Question:
The distance between the ends of wings of an aeroplane is $5\, m$. The aeroplane is moving with velocity of $200\, km/sec$ in a magnetic field of $10\, T.$ The emf induced across the ends of wings will be:
The distance between the ends of wings of an aeroplane is $5\, m$. The aeroplane is moving with velocity of $200\, km/sec$ in a magnetic field of $10\, T.$ The emf induced across the ends of wings will be:
Updated On: Oct 26, 2023
- $ 10^{7} $ volt
- $10$ volt
- $ 10^{6} $ volt
- none of these
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The Correct Option is A
Solution and Explanation
$e=B v l\,\,\,\,...(i)$
Here $: B=10\, T , v=200 \,km / sec$
$=2 \times 10^{5}\, m / sec , l=5\, m$
Putting given values is eq (i)
$\therefore e =10 \times 2 \times 10^{5} \times 5 $
$=1 \times 10^{7}$ volt
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
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