Question

The dip slip on a fault \( 000^\circ, 30^\circ E \) is 10 m. Assuming slip equals separation here, the throw on the fault is .............. m (answer in one decimal place).

Hint:

To calculate the throw on a fault, use the sine of the dip angle multiplied by the total slip.

Answer 1

Correct Answer: 5

Step 1: Understanding the fault geometry.
The fault dip is given as \( 000^\circ, 30^\circ E \), and the slip equals the separation on the fault. The throw on the fault corresponds to the vertical displacement of the fault. The horizontal component is not needed since we're asked for the throw, which only depends on the vertical displacement.

Step 2: Calculation.
For a dip of 30° and a slip of 10 m, the throw is calculated using trigonometric functions. The throw is the vertical component of the displacement, given by: \[ \text{Throw} = 10 \, \text{m} \times \sin(30^\circ) = 10 \times 0.5 = 5.0 \, \text{m} \]

Step 3: Conclusion.
The throw on the fault is 5.0 m.