Question:

The differential equation of the family of hyperbolas having their centers at origin and their axes along the coordinate axes is:

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For obtaining the differential equation of a family of curves, differentiate the given equation repeatedly and eliminate any arbitrary constants or parameters.
Updated On: Mar 24, 2025
  • xyy2+xy12yy1=0 xy y_2 + xy_1^2 - yy_1 = 0
  • xy2xyy12+yy1=0 xy_2 - xy y_1^2 + yy_1 = 0
  • xy2+xy12+yy1=0 xy_2 + xy_1^2 + yy_1 = 0
  • xy2+xy12yy1=0 xy_2 + xy_1^2 - yy_1 = 0
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The Correct Option is A

Solution and Explanation


Step 1: General Equation of Hyperbola
The general equation of a hyperbola centered at the origin with axes along the coordinate axes is: x2a2y2b2=1. \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1. This represents a family of hyperbolas where a a and b b are parameters. Step 2: Eliminating Parameters
To obtain the differential equation, we differentiate the given equation with respect to x x : 2xa22yy1b2=0. \frac{2x}{a^2} - \frac{2yy_1}{b^2} = 0. Differentiating again: 2a22(y12+yy2)b2=0. \frac{2}{a^2} - \frac{2(y_1^2 + yy_2)}{b^2} = 0. Multiplying throughout by b2 b^2 and simplifying: xyy2+xy12yy1=0. xy y_2 + xy_1^2 - yy_1 = 0. Step 3: Conclusion
Thus, the required differential equation of the family of hyperbolas is: xyy2+xy12yy1=0. \boxed{xy y_2 + xy_1^2 - yy_1 = 0.}
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