Question:

The dielectric strength of a medium is $2\,kVmm^{-1}$ . What is the maximum potential difference that can be set up across a $50\,pm$ specimen without puncturing it.

Updated On: Jul 7, 2022
  • 10 V
  • 100 V
  • 1000 V
  • 10000 V
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The Correct Option is B

Solution and Explanation

Dielectric strength = Potential difference gradient. Hence maximum potential difference = Dielectric strength $\times$ distance = $\frac{2000\, V}{mm} \times 50 \, \mu m = \frac{2000 \, V}{10^{-3} \, m} \times 50 \times 10^{-6} m$ = 100 V.
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Notes on Electrostatic potential

Concepts Used:

Electrostatic Potential

The electrostatic potential is also known as the electric field potential, electric potential, or potential drop is defined as “The amount of work that is done in order to move a unit charge from a reference point to a specific point inside the field without producing an acceleration.”

SI Unit of Electrostatic Potential:

SI unit of electrostatic potential - volt

Other units - statvolt

Symbol of electrostatic potential - V or φ

Dimensional formula - ML2T3I-1

Electric Potential Formula:

The electric potential energy of the system is given by the following formula:

U = 1/(4πεº) × [q1q2/d]

Where q1 and q2 are the two charges that are separated by the distance d.