Step 1: Understanding the derivative of exponential functions.
The derivative of \( a^x \), where \( a \) is a constant, is given by the formula \( \frac{d}{dx}(a^x) = \ln(a) \cdot a^x \). In this case, \( a = 2 \), so the derivative of \( 2^x \) is \( \ln(2) \cdot 2^x \).
Step 2: Analyzing the options.
- (A) \( \ln(x) \cdot 2^x \): This is incorrect because the derivative involves \( \ln(2) \), not \( \ln(x) \).
- (B) \( x \cdot 2^{x-1} \): This is incorrect. The correct formula for the derivative does not involve multiplying by \( x \).
- (C) \( \ln(2) \cdot 2^x \): Correct — This is the correct derivative of \( 2^x \) with respect to \( x \).
- (D) \( 2 \cdot 2^{x-1} \): This is incorrect. It does not represent the derivative of \( 2^x \).
Step 3: Conclusion.
The correct answer is (C) because the derivative of \( 2^x \) with respect to \( x \) is \( \ln(2) \cdot 2^x \).
In an experiment to examine the role of exopolymetric substances (EPS) on bacterial growth, a wild-type strain (S⁺) and a mutant strain deficient in EPS production (S⁻) were grown in monocultures as well as in co-culture (in equal proportion of S⁺ and S⁻). The CFU (colony forming units) of these cultures measured after 24 hours are shown in the following figure. 
Which one of the following phenomena best describes the interaction between the wild-type strain (S⁺) and mutant strain (S⁻)?
Match the diseases in Group A with their corresponding causative microorganisms in Group B 
Match the metabolic pathways in Group A with corresponding enzymes in Group B 
Which one of the following matches is CORRECT between the microorganisms given in Group A with their requirement of oxygen in Group B? 