Question:

The decreasing order of reactivity towards dehydrohalogenation (\(E_1\)) reaction of the following compounds is: \begin{center} \includegraphics[width=0.6\textwidth]{VITEEE8.png} \end{center} (A) \( D>B>C>A \)

Show Hint

In \(E_1\) reactions, the rate-determining step is the formation of the carbocation. The more stable the carbocation, the faster the reaction.
Updated On: Feb 12, 2025
  • \( D>B>C>A \)
  • \( B>D>A>C \)
  • \( B>D>C>A \)
  • \( B>A>D>C \)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Understanding the \(E_1\) Mechanism
The \(E_1\) (unimolecular elimination) reaction involves the formation of a carbocation intermediate.
The stability of the carbocation determines the reactivity: the more stable the carbocation, the faster the reaction.
Step 2: Analyzing the Given Compounds

The compounds contain halides (\(\text{Cl}\)) attached to different carbon atoms.
The reactivity order depends on the stability of the carbocation formed after the loss of \(\text{Cl}^-\).
Step 3: Determining the Order of Reactivity

(A) Primary Carbocation: Least stable, leading to the slowest reaction.
(B) Carbocation Undergoing Rearrangement: Results in a more stable secondary or tertiary carbocation, enhancing reactivity.
(C) Five Hyperconjugating Structures: Provides moderate stability.
(D) Resonance-Stabilized Carbocation: Most stable due to delocalization, increasing reactivity.
Step 4: Final Order of Reactivity

The stability of carbocations follows: \[ D>B>C>A \] Final Answer: The correct order is \( D>B>C>A \).
Was this answer helpful?
0
0

Questions Asked in VITEEE exam

View More Questions