Question

The de Broglie wavelength of an electron accelerated through 100 V is approximately:

• A. 1.23 \AA
• B. 12.3 \AA
• C. 0.123 \AA
• D. 123 \AA

Hint:

For electrons, \(\lambda(\text{\AA})=\frac{12.27}{\sqrt{V}}\).

Answer 1

The Correct Option is A

\[ \lambda(\text{\AA})=\frac{12.27}{\sqrt{V}} \Rightarrow \lambda=\frac{12.27}{10}\approx1.23\ \text{\AA} \]