The curve passing through the point (1, 2) given that the slope of the tangent at any point (x, y) is \(\frac{2x}{y}\) represents which type of curve?
The slope of the tangent at any point is \(\frac{dy}{dx} = \frac{2x}{y}\).
We can separate variables to solve this differential equation:
\(y \, dy = 2x \, dx\)
Integrate both sides:
\(\int y \, dy = \int 2x \, dx\)
\(\frac{y^2}{2} = x^2 + C\)
\(y^2 = 2x^2 + 2C\)
Since the curve passes through (1, 2), we can substitute x = 1 and y = 2 to find C:
\(2^2 = 2(1)^2 + 2C\)
\(4 = 2 + 2C\)
\(2 = 2C\)
\(C = 1\)
So the equation of the curve is \(y^2 = 2x^2 + 2\). Rearranging, we get \(y^2 - 2x^2 = 2\), or \(\frac{y^2}{2} - x^2 = 1\).
This is the equation of a hyperbola.
Therefore, the correct option is (D) Hyperbola.