Question:
The counting rate observed from a radioactive source at t = 0 seconds was 1600 counts per second and t = 8 seconds it was 100 count per second. The counting rate observed, as counts per second at t = 6 seconds will be :
The counting rate observed from a radioactive source at t = 0 seconds was 1600 counts per second and t = 8 seconds it was 100 count per second. The counting rate observed, as counts per second at t = 6 seconds will be :
Updated On: Jul 7, 2022
- 400
- 300
- 200
- 150
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The Correct Option is C
Solution and Explanation
After 8 seconds, the counting rate falls to (1 / 16)th = $\left( \frac{1}{2}\right)^4$th part. Hence time period is (8/4) s = 2s. Therefore after 6 second the counting rate should be $(1/2)^3$ th part of
1600. i.e. it should be $\frac{1}{8} \times$ 1600 = 200
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Concepts Used:
Decay Rate
The disintegration of unstable heavy atomic nuclei into lighter, more stable, atomic nuclei, accompanied in the process by the emission of ionizing radiation (alpha particles, beta particles or gamma rays). This is a random process at the atomic level but, given a large number of similar atoms, the decay rate on average is predictable, and is usually measured by the half-life of the substance.
The equation for finding out the decay rate is given below:
