Question:
The correct order of electronegativity of group 13 elements is
The correct order of electronegativity of group 13 elements is
Show Hint
Electronegativity decreases as you go down a group because atomic size increases, which reduces the ability of the nucleus to attract bonding electrons.
Updated On: Jun 6, 2025
- B > Ga > Al > Tl > In
- B > Al > Tl > Ga > In
- B > Al > Ga > In > Tl
- B > Tl > In > Ga > Al
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
The electronegativity of group 13 elements decreases as we move down the group. B has the highest electronegativity, followed by Al, Ga, In, and Tl. Thus, the correct order is B > Al > Ga > In > Tl.
Was this answer helpful?
0
0
Top Questions on Metallurgy
- Complete hydrolysis of Xenon hexafluoride gives HF along with compound X. The hybridisation in X is
- AP EAPCET - 2025
- Chemistry
- Metallurgy
- The number of amphoteric oxides from the following is
\(\mathrm{CO_2, GeO_2, SnO_2, PbO_2, CO, GeO, SnO, PbO}\)- AP EAPCET - 2025
- Chemistry
- Metallurgy
- Which of the following methods is useful for producing semiconductor grade metals of high purity?
- AP EAPCET - 2025
- Chemistry
- Metallurgy
- Consider the following: Statement-I: In the extraction of Al by Hall-Heroult process, pure \( Al_2O_3 \) mixed with \( Na_3AlF_6 \) lowers its melting point and increases conductivity. Statement-II: Zirconium metal is purified by zone refining method. The correct answer is:
- AP EAPCET - 2025
- Chemistry
- Metallurgy
- Identify the reaction in which diborane is produced on an industrial scale:
- AP EAPCET - 2025
- Chemistry
- Metallurgy
View More Questions
Questions Asked in AP EAPCET exam
- Two blocks of masses 8 kg and 12 kg kept on a smooth horizontal table are connected to the ends of a light string as shown in the figure. If a horizontal force of 500 N is applied to the block of mass 12 kg, then the tension in the string connecting the blocks is
- AP EAPCET - 2025
- laws of motion
- If the normal drawn to the hyperbola \( xy = 16 \) at (8, 2) meets the hyperbola again at a point \((\alpha, \beta)\), then \( |\beta| + \frac{1}{|\alpha|} = \)
- AP EAPCET - 2025
- Hyperbola
- If the binding energy per nucleon of deuteron (\( ^1\mathrm{H}^2 \)) is 1.15 MeV and an \(\alpha\)-particle has a binding energy of 7.1 MeV per nucleon, then the energy released per nucleon in the given reaction is \[ ^1\mathrm{H}^2 + ^1\mathrm{H}^2 \rightarrow ^2\mathrm{He}^4 + Q \]
- AP EAPCET - 2025
- Nuclear physics
- If the function \( f \) defined by \[ f(x) = \begin{cases} \dfrac{1 - \cos 4x}{x^2}, & x<0 \\ a, & x = 0 \\ \dfrac{\sqrt{x}}{\sqrt{16 + \sqrt{x}} - 4}, & x>0 \end{cases} \] is continuous at \( x = 0 \), then \( a = \)
- AP EAPCET - 2025
- Limits and Exponential Functions
If \( \vec{u}, \vec{v}, \vec{w} \) are non-coplanar vectors and \( p, q \) are real numbers, then the equality:
\[ [3\vec{u} \quad p\vec{v} \quad p\vec{w}] - [p\vec{v} \quad \vec{w} \quad q\vec{u}] - [2\vec{w} \quad q\vec{v} \quad q\vec{u}] = 0 \]
holds for:
- AP EAPCET - 2025
- Geometry and Vectors
View More Questions
