Question:

The correct match between the physical states of the soils given in Group I and the governing conditions given in Group II is 

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For soils, understanding their consolidation, plasticity, and sensitivity helps in matching them with their corresponding physical conditions.
Updated On: Jan 11, 2026
  • 1-S, 2-P, 3-Q, 4-R
  • 1-Q, 2-S, 3-P, 4-R
  • 1-Q, 2-P, 3-R, 4-S
  • 1-S, 2-Q, 3-P, 4-R
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The Correct Option is A

Solution and Explanation

Step 1: Understanding Group I.
- (1) Normally consolidated soil: This is soil that has not been subjected to any significant overburden pressure, meaning its over-consolidation ratio is 1. Hence, it matches with (S) over consolidation ratio = 1.
- (2) Quick clay: This is clay that has a high sensitivity (ratio of strength in undisturbed vs disturbed state), typically greater than 16. Hence, it matches with (P) sensitivity > 16.
- (3) Sand in critical state: In this state, the dilation angle of sand is zero, which indicates no volume change during shear. Hence, it matches with (Q) dilation angle = 0.
- (4) Clay of high plasticity: Clay with a high liquid limit (greater than 50) is classified as high plasticity. Hence, it matches with (R) liquid limit > 50.

Step 2: Conclusion.
Based on the analysis, the correct match is (A): 1-S, 2-P, 3-Q, 4-R.

Final Answer: \[ \boxed{1-S, 2-P, 3-Q, 4-R} \]

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